How do you simplify $4 \sqrt{3} + 2 \sqrt{12}$ $4\sqrt{3}+2\sqrt{12}$ ?

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Answer 1 · 2018-05-29T03:33:08

$4 \sqrt{3} + 2 \sqrt{12} = 8 \sqrt{3}$ $4sqrt3+2sqrt12=color(blue)(8sqrt3$

Simplify:

$4 \sqrt{3} + 2 \sqrt{12}$ $4sqrt3+2sqrt12$

We can only add or subtract numbers with radicals if the radicals are the same.

Prime factorize $\sqrt{12}$ $sqrt12$ .

$4 \sqrt{3} + 2 \sqrt{2 \times 2 \times 3}$ $4sqrt3+2sqrt(2xx2xx3)$

Write the factorization in exponent form.

$4 \sqrt{3} + 2 \sqrt{2^{2} \times 3}$ $4sqrt3+2sqrt(2^2xx3)$

Apply rule: $\sqrt{a^{2}} = a$ $sqrt(a^2)=a$

$4 \sqrt{3} + 2 \times 2 \sqrt{3}$ $4sqrt3+2xx2sqrt3$

Simplify $2 \times 2$ $2xx2$ to $4$ $4$ .

$4 \sqrt{3} + 4 \sqrt{3}$ $4sqrt3+4sqrt3$

Simplify.

$8 \sqrt{3}$ $8sqrt3$

How do you simplify 4\sqrt{3}+2\sqrt{12}4√3+2√124\sqrt{3}+2\sqrt{12}?