How do you solve #3|2x+11|+2<17#?

Question

1515 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-29T04:19:45

Solution: # x in -8 < x <-3 or x in (-8,-3)#

#3 |2 x + 11| +2 <17 or 3 |2 x + 11| <15 # or

#|2 x + 11| <15/3 or |2 x + 11| < 5#

a) # 2 x + 11 < 5 or 2 x < 5-11# or

# 2 x < - 6 or x < -6/2 or x < -3 # OR

b) # 2 x + 11 > -5 or 2 x > -5-11# or

# 2 x > - 16 or x > -16/2 or x > -8 #

Solution: # x in -8 < x <-3 or x in (-8,-3)# [Ans]