It takes 3,190 J to increase the temperature of a 0.400 kg sample of glass from 273 K to 308 K. What is the specific heat for this type of glass?
1 Answer
May 29, 2018
Explanation:
Specific heat is given by
#"S" = "Q"/"mΔT"#
Where
#"Q ="# Heat added/liberated#"m ="# Mass of sample#"ΔT ="# Change in temperature
