Question

How do you find the x-coordinate of the vertex for the graph `4x^2+16x+12=0`?

Answer 1

`x=-2`

Explanation:

Your quadratic equations is in standard form `ax^2+bx+c` so the x-coordinate of the vertex (also called the axis of symmetry) is found with the formula:

`aos=(-b)/(2a)`

`4x^2+16x+12`

`aos=(-16)/(2*4) = -2`

graph{4x^2+16x+12 [-10, 10, -5, 5]}