What is the area between #f(x)=x^2-4x+3# and #g(x)=3-x# from x=0 to x=3?

Find the area between #f(x)=x^2-4x+3# and #g(x)=3-x# from x=0 to x=3

1 Answer
Jonny
May 29, 2018

I got #9/2#
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Explanation:

I'm new to this but I think it's right.
first i determined where the functions cross, and then I figured out which function was on top and which was on bottom. Then i took the integral of g(x)-f(x) from 0 to 3 and I got #9/2#

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