How do you graph using the intercepts for x+2y=5?

2 Answers
May 30, 2018

See below

Explanation:

To find the intercepts, substitute in x=0 to find the y-intercept and y=0 to find the x-intercept, so:

Substitute x=0 into x+2y=5
0+2y=5
2y=5
y=5/2
Therefore, the y-intercept is y=5/2, also written as y=2.5

Substitute y=0 into x+2y=5
x+2(0)=5
x=5
Therefore, the x-intercept is x=5

If you do not already know so, the x-intercept is where the line touches or crosses through the x-axis and the y-intercept is where the line touches or crosses through the y-axis.

Now that you know the intercepts, simply indicate on the graph the points (5, 0)(the x-intercept) and (0, 2.5) (the y-intercept) and draw a line connecting the dots, so the graph would be:

graph{x+2y=5 [-7.54, 12.46, -3.48, 6.52]}

May 30, 2018

x+2y=5
graph{(x^2+(y-5/2)^2-0.01)((x-5)^2+y^2-0.01)(x+2y-5)=0 [-2.59, 7.273, -0.85, 4.08]}

Explanation:

Given the linear equation x+2y=5

#{:
(x"-intercept=value of "x" when "y=0," | ",y=0rArrx=5," | ","point: "(5,0)),
(y"-intercept=value of "y" when "x=0," | ",x=0rArry=5/2," | ","point: "(0,5/2))

Plotting each of the two points on the Cartesian plane and drawing a line through them gives the graph shown in the Answer.
:}#