How do you solve 2e^x-1=7? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Roy D. May 31, 2018 x = ln(4) \approx 1.386294361... Explanation: 2e^x-1+1 = 7+ 1 = 8 \frac{2e^x}{2} = \frac{8}{2} = 4 ln(e^x) = ln(4) x = ln(4) Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 2559 views around the world You can reuse this answer Creative Commons License