How do you simplify $-2y^3(3x^2y - 6x^2y^2)$ ?

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Answer 1 · 2018-06-01T10:54:30

$-2y^3(3x^2y-6x^2y^2)=color(blue)(-6x^2y^4+12x^2y^5$

Simplify:

$-2y^3(3x^2y-6x^2y^2)$

Distribute $-2y^3$ .

$(-2y^3*3x^2y)-(-2y^3*6x^2y^2)$

Simplify parentheses.

$-2y^3*3x^2y+2y^3*6x^2y^2$

Multiply constants.

$-6y^3*x^2y+12y^3*x^2y^2$

Group like variables.

$-6x^2y^3y+12x^2y^2y^3$

Apply product rule: $a^ma^n=a^(m+n)$

$-6x^2y^(3+1)+12x^2y^(2+3)$

Simplify.

$-6x^2y^4+12x^2y^5$

Answer 2 · 2018-06-01T10:55:22

$-6x^2y^2+12x^2y^3$

Expanding we get
$-6x^2y^2+12x^2y^3$

How do you simplify -2y^3(3x^2y - 6x^2y^2)-2y^3(3x^2y - 6x^2y^2)?