If 425.0 g of mercury at 25.0 degrees Celsius absorbs .750 Kilo joules of heat energy, what will be it's final temperature?

1 Answer
Jun 1, 2018

#"37.6°C"#

Explanation:

Use this equation

#"Q = mSΔT"#

Where

#"ΔT" = "Q"/"mS"#

#"T"_f - "T"_i = "Q"/"mS"#

#"T"_f = "T"_i + "Q"/"mS"#

#color(white)("T"_f) = "25.0°C" + "750 J"/"425.0 g × 0.14 J/g°C"#

#color(white)("T"_f) = "25.0°C + 12.6°C"#

#color(white)("T"_f) = "37.6°C"#