Question

How do you find the standard form of `x^2 + y^2 + 2x - 6y - 6 = 0` and what kind of a conic is it?

Answer 1

Circle, radius 4 and centre (-1,3)

Explanation:

`x^2+2x+y^2-6y=6`

`(x+1)^2-1+(y-3)^2-9=6`

`(x+1)^2+(y-3)^2=16`