If #f(x) = 2/3x^2 + 8x#, what is the value of #f(6)#?

1 Answer
Jun 1, 2018

#f(6)=72#

Explanation:

#"to evaluate "f(6)" substitute x = 6 into "f(x)#

#f(color(red)(6))=2/3xx(color(red)(6))^2+(8xxcolor(red)(6))#

#color(white)(xxx)=2/cancel(3)^1xxcancel(36)^(12)+48#

#color(white)(xxx)=24+48=72#