#24x+16# how do you factorise fully ?

3 Answers
Jun 1, 2018

#8(3x+2)#

Explanation:

Finding the highest common factors that go into both numbers:

Factors of #24#:

#24 and 1#
#12 and 2#
#8 and 3#
#6 and 4#

Factors of #16#:

#16 and 1#
#8 and 2#
#4 and 4#

As we can see, #8# is the HCF (highest common factor) in both numbers, so we factor this outside the bracket.

#rArr 8(...+...)#

#therefore# #8# needs to multiply into #24x# and #16#

#rArr 8 xx 3x=24x#

#rArr 8 xx 2=16#

#therefore# #rArr 8(3x+2)=24x+16#

Jun 1, 2018

#8(3x+2)#

Explanation:

#"take out a "color(blue)"common factor "8#

#=8(3x+2)#

Jun 1, 2018

#8(3x+2)#

Explanation:

Find the common factors of #24# and #16# (numbers that multiply to give #24# and #16# respectively):

#24: 1, 2, 3, 4, 6, 8, 12, 24#
#16: 1, 2, 4, 8, 16#

Then find the highest common factor of #24# and #16# which is #8#.

Take 8 to be on the outside of the bracket as this will be the number the terms would be multiplied by to give #24x# and #16#. Divide each term by #8# and you should get:

#8(3x+2)#

This is the fully factorised form of #24x+16#.