How do you find the intercepts for #y= -5/(3x)+ 2#?

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Answer 1 · 2018-06-01T21:25:38

#x=6/5#

#y=2#

#y= -5/(3x)+ 2#

#y= -5/3x+ 2#

to find y intercept set x=0 and solve for y:

#y= -5/3*0+ 2#

#y=2#

to find x intercept set y = 0 and solve for x:

#0= -5/3x+ 2#

#-2= -5/3x#

#-2*-3/5= -5/3x * -3/5#

#6/5=x#

#x=6/5#