How do you simplify 6[(z^2 +3 (0+2)] when z is -4?

2 Answers
Jun 2, 2018

132

Explanation:

Let's simplify the inside first. 0+2 obviously simplifies to 2, and multiplying it by 3 will yield 6. Now, we have

6(z^2+6)

Plugging in z=-4, we get

6((-4)^2+6)

=>6(16+6)

=>6(22)

=>132

Hope this helps!

Jun 2, 2018

132

Explanation:

As per the question, we have

6[z^2 + 3(0 + 2)]

:. At z = -4, we get

6[(-4)^2 + 3(2)]

= 6(16 + 6)

= 6(22)

= 132

Hence, the answer.