How do you solve #2/y=10/60#?

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Answer 1 · 2018-06-02T09:15:32

#y=12#

#2/y=10/60#

method 1

invert the fractions

#=>y/2=60/10#

#=>y=60/10xx2#

#:.y=6xx2=12#

method 2

cancel the fractions and compare

#y/2=60/10=6/1#

note by multiplying the second denominator by 2 we get the first denominator

so

#y=6xx2=12#

Answer 2 · 2018-06-02T09:16:04

#y=12#

Taking the reciprocal value then we get
#y/2=60/10#
so
#y=120/10=12#