Question

How do you solve `3c + 7= 22`?

Answer 1

`c=5`

Explanation:

`"isolate "3c" by subtracting 7 from both sides"`

`3c cancel(+7)cancel(-7)=22-7`

`3c=15`

`"divide both sides by 3"`

`(cancel(3) c)/cancel(3)=15/3rArrc=5`

`color(blue)"As a check"`

`(3xx5)+7=15+7=22="right side"`

`c=5" is the solution"`