How do you simplify #(7a-5)^2#?

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Answer 1 · 2018-06-02T11:11:07

#49a^2-70a+25#

#(7a-5)^2#
#(7a-5)(7a-5) = 49a^2-35a-35a+25#
#49a^2-70a+25#

Answer 2 · 2018-06-02T11:14:32

we get #49a^2-70a+25#

Use the Formula
#(A-B)^2=A^2-2AB+B^2#
with
#A=7a,B=5#