How many molecules #"NH"_3# can be produced from #3.0xx10^24# molecules of #"H"_2#? #"N"_2 + "3H"_2"##rarr##"2NH"_3#

1 Answer
Meave60
Jun 2, 2018

#2.0xx10^24# #"molecules NH"_3"# can be produced from #3.0xx10^24# #"molecules H"_2"#.

Explanation:

Balanced equation

#"N"_2 + "3H"_2"##rarr##"2NH"_3"#

The ratio between #"NH"_3"# and #"H"_2"# is #2:3#.

#3.0xx10^24color(red)cancel(color(black)("molecules H"_2))xx(2"molecule NH"_3)/(3color(red)cancel(color(black)("molecules H"_2)))=2.0xx10^24# #"molecules NH"_3"#

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