Can anybody solve this?

9x^2 + 16y^2+36x-32y-92 = 0

1 Answer
Jun 3, 2018

x approx {-5.771, 1.771}

Explanation:

9x^2 + 16y^2+36x-32y-92 = 0

9x^2 + 16y^2+36x-32y = 92

The above constitutes an ellipse as shown below.

graph{9x^2 + 16y^2+36x-32y = 92 [-10, 10, -5, 5]}

From which we can determine the x-intercepts as:

x approx {-5.771, 1.771}