How do you solve #-10x-9+11+x=-2(2x+4)-5(x-2)#?

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Answer 1 · 2018-06-03T14:42:35

#x in RR#

As per the question, we have

#-10x-9+11+x=-2(2x+4)-5(x-2)#

#:.-9x + 2 = -4x-8-5x+10#

#:.-9x+2=-9x+2#

#:.-9x=-9x#

#:.0=0#

#:.# Both sides are equal.

#:.# This equation is true for all #x#.

Hence, #x in RR#