How do you write an equation in point slope form that passes through Point: (1, –7); Slope: -2/3?

Question

7992 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-03T22:06:22

#y+7=-2/3(x-1)#

Given a point:

#(x_1, y_1) = (1, -7)#

and a slope:

#m=-2/3#

Point slope form is:

#y-y_1=m(x-x_1)#

#y-(-7)=-2/3(x-1)#

#:. y+7=-2/3(x-1)#

graph{y+7=-2/3(x-1) [-14.96, 5.04, -8.44, 1.56]}

Answer 2 · 2018-06-03T22:06:38

See a solution process below:

The point-slope form of a linear equation is: #(y - color(blue)(y_1)) = color(red)(m)(x - color(blue)(x_1))#

Where #(color(blue)(x_1), color(blue)(y_1))# is a point on the line and #color(red)(m)# is the slope.

Substituting the information from the problem gives:

#(y - color(blue)(-7)) = color(red)(-2/3)(x - color(blue)(1))#

#(y + color(blue)(7)) = color(red)(-2/3)(x - color(blue)(1))#