How do you solve the following system: #3x+2y =0, -5x − y = 14 #?

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Answer 1 · 2018-06-04T04:31:29

#x=-4#

#y=6#

#{(3x+2y=0), (-5x-y=14):}#

Do

#3x+2y=0#
#2(-5x-y=14)#

#3x+2y=0#
#-10x-2y=28#

Add the two equations

#-7x=28#

So

#x=28/-7#

#x=-4#

Use #x = -4# in the first equation

#3(-4)+2y=0#

#-12+2y=0#

#2y=12#

#y=12/2=6#