How do you solve #m- 3= \frac { 4} { 6} m - 2#?

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Answer 1 · 2018-06-04T11:11:34

#m = 3#

Firstly, multiply both sides by 6 as the #4/6m# looks ugly and we don't want it

#6m - 18 = 4m-12#

from there, take the 4m over so it ends up being #6m-4m-18=-12# simplify #2m-18 = -12#

next, move the constants to one side, i'll move the -18 over making + 18, so that #2m=6# and thus #m=3#

Answer 2 · 2018-06-04T12:50:32

#m=3#

#m-3=4/6m-2#

multiply both sides by #6#

#:.6m-18=4m-12#

#:.6m-4m-18+12=0#

#:.2m-6=0#

#:.2m=6#

#:.m=6/2#

#:.m=3#