How do you solve $- 5 + 2 ln (3 x) = 5$ $-5+2ln(3x)=5$ ?

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Answer 1 · 2018-06-04T17:32:36

$x = \frac{e^{5}}{3}$ $x=e^5/3$

Writing
$2 ln (3 x) = 10$ $2ln(3x)=10$
so
$ln (3 x) = 5$ $ln(3x)=5$
and we have

$ln (3 x) = ln (e^{5})$ $ln(3x)=ln(e^5)$

so

$3 x = e^{5}$ $3x=e^5$

$x = \frac{e^{5}}{3}$ $x=e^5/3$

How do you solve -5+2ln(3x)=5−5+2ln(3x)=5-5+2ln(3x)=5?