How do you simplify #35/6 + 7/12 - 1 1/3#?

2 Answers
Jun 4, 2018

Make all fractions improper, make the denominators the same, perform the addition and subtraction.

Explanation:

First, make the third fraction improper by multiplying #3# by #1# and adding #1#. So, it will turn out to be

#1 1/3 = (3 xx 1 + 1)/3 = 4/3#

So #12# will be our common denominator.

Multiply #35/6# times #2/2# in order to make the denominator equal to twelve. Likewise, multiply #4/3# times #4/4# to make the denominator equal to twelve.

#35/6 xx 2/2 = 70/12#

#4/3 xx 4/4 = 16/12#

Once this is done, you have all your fractions under a common denominator, and you can now add and subtract.

#70/12 + 7/12 - 16/3 = (70 + 7 - 16)/12 = 61/12#

This result cannot be simplified further as #61# and #12# do not have common factors. So, your result would end up being #61/12#.

Jun 5, 2018

#61/12 or 5 1/12#

Explanation:

#35/6+7/12-1 1/3#

#:.=35/6+7/12-4/3#

#:.=(70+7-16)/12#

#:.=61/12 or 5 1/12#