A gas sample in a rigid container at 455 K is brought to STP (273K and 1 atm). What was the original pressure of the gas in mmHg?

1 Answer
Jun 4, 2018

#1266.67\ "mmHg"#

Explanation:

From Gay-Lussac's law

#color(white)(...)"P ∝ T"#

#"P"_1/"P"_2 = "T"_1/"T"_2#

#"P"_1 = "P"_2 × "T"_1/"T"_2#

#color(white)("P"_1) = "1 atm" × "455 K"/"273 K"#

#color(white)("P"_1) = 5/3\ "atm"#

#color(white)("P"_1) = 5/3 cancel"atm" × "760 mmHg"/(1 cancel"atm")#

#color(white)("P"_1) = 1266.67\ "mmHg"#