How do you solve $2 - 5 (x - 5) \leq 7 x + 15$ $2- 5( x - 5) \leq 7x + 15$ ?

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Answer 1 · 2018-06-05T02:04:15

$x \geq 1$ $x >= 1$

Start with

$2 - 5 (x - 5) \leq 7 x + 15$ $2-5(x-5) <= 7x+15$

Distribute the LHS

$2 - 5 x + 25 \leq 7 x + 15$ $2-5x+25 <= 7x+15$

Combine like terms on the LHS

$- 5 x + 27 \leq 7 x + 15$ $-5x+27 <= 7x + 15$

Add $5 x$ $5x$ to both sides

$27 \leq 12 x + 15$ $27 <= 12x + 15$

Subtract $15$ $15$ from both sides

$12 \leq 12 x$ $12 <= 12x$

Divide both sides by $12$ $12$

$1 \leq x$ $1 <= x$

How do you solve 2- 5( x - 5) \leq 7x + 152−5(x−5)≤7x+152- 5( x - 5) \leq 7x + 15?