Solve for x?

Question

If #y = a log_10 x#, find x when a = 2 and y = 3

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Answer 1 · 2018-06-05T13:56:56

I tried this:

Let us rearrange it and use our values:

#log_(10)x=y/a#

#log_(10)x=3/2#

use the definition of log:

#x=10^(3/2)#

use the property of exponents:

#x=sqrt(10^3)#

giving:

#x=10sqrt(10)=31.62#

Answer 2 · 2018-06-05T14:09:46

#x approx 31.622777#

#3 = 2log_10 x#

#log_10 x= 3/2#

#x= 10 ^(3/2)#

#x approx 31.622777#