Question

What is the vertex of the parabola whose equation is `y=(x+1)^2+3`?

Answer 1

`(-1, 3)`

Explanation:

This equation is in vertex form `y=a(x-h)^2+k`, where `(h, k)` represents the vertex

Here, `a` is `1`, `h` is `-1`, and `k` is `3`

The vertex is `(-1, 3)`