How do you simplify #root5(32x^6)#?

Question

2074 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-05T18:41:54

#=2xroot5(x)#

#=root5(32x^6)#

#=root5(32x^5 *x)#

#=xroot5(32*x)#

#=xroot5(2*2*2*2*2*x)#

#=xroot5(2^5*x)#

#=2xroot5(x)#

Answer 2 · 2018-06-05T18:49:36

My thought

#root(5) (32*x^6)=root(5)32*root(5) (x^5*x)=2*x*root(5)x#