How can you solve #((x+y)/(x-z))^x#?

Question

x=2, y=-4, z=-5

1241 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-05T23:48:39

#4/49#

Replace the variables with the corresponding numbers:

#((2+(-4))/(2-(-5)))^2#

Then use order of operations. First parentheses:

#((-2)/7)^2#

Then exponents (squaring a fraction squares the numerator and denominator):

#4/49#

We are done!