How do you solve #-3x^2 - x + 2 = 0#?

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Answer 1 · 2018-06-06T02:53:13

#x = -1, 2/3#

#-3x^2-x+2=0#

#(−3x+2)(x+1) = 0#

Solving for the first solution

#-3x+2=0#

#-3x = -2#

#x = 2/3#

Solving for the second solution

#x+1 = 0#

#x = -1#