2AL (s) + 6HCL3(aq) rarr 2AlCl3(aq) + 3H2(g) 0.040 mol piece of aluminium reacted completely in 20s. the rate of formation of hydrogen gas is?

2AL (s) + 6HCL3(aq) rarr 2AlCl3(aq) + 3H2(g)

1 Answer
Jun 6, 2018

0.003 "mol/s"

Explanation:

From the equation, we can see that the ratio of number of moles:

Al : HCl : AlCl3 : H2 (Assuming that HCl3 was a typo)

is equal to:

2 : 6 : 2 : 3 (As the numbers in front of each substances show)

Therefore, if 0.040 mol of aluminium reacted completely, than 0.040 \times 3/2 = 0.060 "mol" of hydrogen was formed.

Thus, 0.060 \divide 20 = 0.003 "mol/s"

Hope that makes sense!