How do you factor $r^2-4r+3$ ?

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Answer 1 · 2018-06-06T09:23:01

$r^2-4r+3=(r-1)*(r-3)$

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$r^2-4r+3$

$(r-1)*(r-3)$

Answer 2 · 2018-06-06T09:24:35

$(r-1)(r-3)$

$"the factors of + 3 which sum to - 4 are - 1 and - 3"$

$r^2-4r+3=(r-1)(r-3)$

Answer 3 · 2018-06-06T09:25:45

$r^2-4r+3=color(blue)((r-1)(r-3)$

Factor:

$r^2-4r+3$

Find two numbers that when added equal $-4$ and when multiplied equal $3$ . The numbers $-1$ and $-3$ meet the requirements.

Rewrite the equation as two binomials.

$r^2-4r+3=(r-1)(r-3)$

How do you factor r^2-4r+3r^2-4r+3?