How do you factor #r^2-4r+3#?

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Answer 1 · 2018-06-06T09:23:01

#r^2-4r+3=(r-1)*(r-3)#

show below:

#r^2-4r+3#

#(r-1)*(r-3)#

Answer 2 · 2018-06-06T09:24:35

#(r-1)(r-3)#

#"the factors of + 3 which sum to - 4 are - 1 and - 3"#

#r^2-4r+3=(r-1)(r-3)#

Answer 3 · 2018-06-06T09:25:45

#r^2-4r+3=color(blue)((r-1)(r-3)#

Factor:

#r^2-4r+3#

Find two numbers that when added equal #-4# and when multiplied equal #3#. The numbers #-1# and #-3# meet the requirements.

Rewrite the equation as two binomials.

#r^2-4r+3=(r-1)(r-3)#