How do you simplify #6/2(1+2) # using order of operations?

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Answer 1 · 2018-06-06T13:58:09

#9#

Given: #6/2(1+2)#.

Divide #6/2# first.

#=3(1+2)#

Add the terms in brackets.

#=3(3)#

Multiply together.

#=9#