What is #(4^2-8)2^3-85-:10#?

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Answer 1 · 2018-06-07T04:51:23

#[(16-8)xx8]-40/10= 64-4=60#

It's actually extremely simple if you know the order of operations.
PEMDAS!

It also goes left to right! So beginning with the parentheses, we focus on what is in the parentheses

#( 4^2 -8)#

meaning #16#, which is the square of #4#, subtracted by #8#. which turns in to #8#.

#( 4^2 -8) = 16 - 8 = 8#

After the paratheses, you multiply by #8# the cube of #2#, which is then subtracted by #4#.

#8 xx 2^3 = 8 xx 8 = 64#

Since, if you follow PEMDAS and multiply then divide from left to right, it's #40/10#, which is #4#. So the answer, in the end, is

#64 - 40/10 = 64 - 4 = 60#

What is #(4^2-8)*2^3-8*5-:10#?