What is the range of the function #f(x)=1/(x+3)#?

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Answer 1 · 2018-06-07T07:49:29

The range is #y in (-oo,0)uu(0,+oo)#

Let #y=1/(x+3)#

#=>#, #y(x+3)=1#

#=>#, #yx+3y=1#

#=>#, #yx=1-3y#

#=>#, #x=(1-3y)/y#

The denominator #!=0#

#y!=0#

The range is #y in (-oo,0)uu(0,+oo)#

graph{1/(x+3) [-10, 10, -5, 5]}