What is the range of the function $f(x)=1/(x+3)$ ?

Question

4431 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-07T07:49:29

The range is $y in (-oo,0)uu(0,+oo)$

Let $y=1/(x+3)$

$=>$ , $y(x+3)=1$

$=>$ , $yx+3y=1$

$=>$ , $yx=1-3y$

$=>$ , $x=(1-3y)/y$

The denominator $!=0$

$y!=0$

The range is $y in (-oo,0)uu(0,+oo)$

graph{1/(x+3) [-10, 10, -5, 5]}

What is the range of the function f(x)=1/(x+3)f(x)=1/(x+3)?