What is the mole fraction of solute in a 3.37 #m# aqueous solution?

1 Answer
anor277
Jun 7, 2018

#chi_"solute"-=0.0572#

Explanation:

We gots a solute that has a MOLAL concentration of #3.37*mol*kg^-1#...and so in #1*kg# of WATER there are #3.37*mol#...

Now #chi_"solute"="moles of solute"/"total mole in solution"#

#(3.37*mol)/(3.37*mol+(1000*g)/(18.01*g*mol^-1))=0.0572#

What is #chi_"water"#?

Related questions
See all questions in Mole Ratios
Impact of this question
11183 views around the world
You can reuse this answer
Creative Commons License