How do you write an equation of a line with slope -4 y intercept 6?

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Answer 1 · 2018-06-07T21:30:10

#y=-4x+6#

We can write this equation in slope-intercept form

#y=mx+b#

where #m# is the slope and #b# is the #y#-intercept.

We know #m=-4# and #b=6#, so we can insert these into the equation to get

#y=-4x+6#

Hope this helps!

Answer 2 · 2018-06-07T21:30:13

#y = -4x+6#

A line has equation

#y = mx+b#

where #m# is the slope and #b# is the y-intercept.

So the equation here would be

#y = -4x+6#