How do you find the product $5 w (- 3 w^{2} + 2 w - 4)$ $5w(-3w^2+2w-4)$ ?

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Answer 1 · 2018-06-08T13:53:49

$- 15 w^{3} + 10 w^{2} - 20 w$ $-15w^3+10w^2-20w$

Use the distributive property, which states that $a (b + c + d) = a b + a c + a d$ $a(b+c+d)=ab+ac+ad$ .

$= 5 w \cdot - 3 w^{2} + 5 w \cdot 2 w - 5 w \cdot 4$ $=5w*-3w^2+5w*2w-5w*4$

$= - 15 w^{3} + 10 w^{2} - 20 w$ $=-15w^3+10w^2-20w$

How do you find the product 5w(-3w^2+2w-4)5w(−3w2+2w−4)5w(-3w^2+2w-4)?