How do you find the midpoint of (2,6) (-1,1)?
1 Answer
Jun 8, 2018
Explanation:
#"given endpoints "(x_1,y_1)" and "(x_2,y_2)" then"#
#"the midpoint of the points is"#
#•color(white)(x)[1/2(x_1+x_2),1/2(y_1+y_2)]#
#"here "(x_1,y_1)=(2,6)" and "(x_2,y_2)=(-1,1)#
#"midpoint "=[1/2(2-1),1/2(6+1)]#
#color(white)(xxxxxxxx)=(1/2,7/2)#
