How do you simplify #8x^2-8- [3(x^2-1) +7]#?

Question

1999 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-08T18:34:01

5#x^2#-12

We will start by expanding the inner brackets.

8#x^2#-8-[3(#x^2#-1)+7]

So it becomes this by multiplying 3 with #x^2# and #-1#

8#x^2#-8-[3#x^2#-3+7]

Then we further simplify the insides of the brackets so it becomes,

8#x^2#-8-[3#x^2#+4]

Then we multiply #-1# with the insides of the bracket, so we get:

8#x^2#-8-3#x^2#-4

Then we bring and simplify like terms together:

8#x^2#-3#x^2#-8-4

This becomes:

5#x^2#-12