Question

How do you solve the following linear system `-2x+y=5, -x + 3y - 2z = 0, 4x - 2y + 7z = 3`?

Answer 1

`x=-79/35,y=17/35,z=13/7`

Explanation:

Multiplying the second equation by `7` and the third equation by `2` and adding them:
`x+17y=6`
multiplying this equation by `2` and adding to the first one:
`y=17/35`
so we get
`-2x+17/35=5`
we obtain
`y=-79/35`
and
`79/35+3*17/35=2z`

so `z=13/7`