How do I solve #(2sqrt2-2)cosalpha=3sin^2alpha+sqrt2-4#?
3 Answers
Explanation:
Replacing
This is a quadr. eqn. in
Therefore, using the quadr. formula, we have,
Explanation:
let
now solve for
since
Explanation:
Solve this quadratic equation for cos x.
There are 2 real roots:
cos x = - 0.54, and cos x = 0.26
a. cos x = - 0.54
Calculator and unit circle give 2 solutions:
b. cos x = 0.26 -->
Check by calculator:
1. x = 74.93 --> 0.83cos x = 0.22 -->
2. x = 122.68 -->