'(1-D^2)^-1 =?'

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Answer 1 · 2018-06-10T17:29:08

#color(magenta)(=>1/[(1-d)(1+d)]#

#(1-d^2)^-1#

Using the law, #color(red)(a^-m=1/a^m#

#=>1/(1-d^2)#

Using the identity, #color(blue)(a^2-b^2=(a+b)(a-b)#

Since # 1=1^2#

#color(magenta)(=>1/[(1-d)(1+d)]#

~Hope this helps! :)