Identify and explain any restrictions on the variable x in the expression #sqrt(4x-2)#?

1 Answer
Jun 10, 2018

See explanation below

Explanation:

Square root is an expresion defined only for postive real numbers. Do not have sense expresions like #sqrt(-1)# because there is no any number #x# such that #x^2=-1#. This type of expresions have solution in a bigger set of numbers called Complex.

In our case #sqrt(4x-2)# we have to be sures that #4x-2# is positive or zero. Then we express this fact by

#4x-2>=0# it's say
#4x>=2#
#x>=2/4#
#x>=1/2#

Thus, our expresion only have sense in #RR# if we choose x bigger or equal to #1/2#

The restriction is #x>=1/2#, or expressed in interval form #[1/2,oo)#