How do you find the x and y intercepts for #y + 4x= 5#?
1 Answer
Jun 10, 2018
Explanation:
#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0rArry+0=5rArry=5larrcolor(red)"y-intercept"#
#y=0rArr0+4x=5rArrx=5/4larrcolor(red)"x-intercept"#
graph{(y+4x-5)((x-0)^2+(y-5)^2-0.04)((x-5/4)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}
