How many different permutation can be made using all letter in the word social science ?

1 Answer

#(13!)/(2!3!2!2!)=("6,227,020,800")/(2xx6xx2xx2)="129,729,600"#

Explanation:

The words "social science" contain 13 letters in all, and of those, we have 2 Ss, 3 Cs, 2 Is, and 2 Es.

If all 13 letters were unique, we'd have #13! = "6,227,020,800"# ways to arrange the letters.

However, because we have duplicate letters, we have to divide out the duplicate arrangements (for instance, note that #S_1S_2...# is the same as #S_2S_1...#). The number of ways the duplicate letters can be internally arranged is equal to how many there are, factorial (and so for the Ss it's #2! =2#, for the Cs its #3! =6#, etc). This gives:

#(13!)/(2!3!2!2!)=("6,227,020,800")/(2xx6xx2xx2)="129,729,600"#