How do you multiply #\sqrt { 20} \cdot \sqrt { 3}#?

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Answer 1 · 2018-06-11T07:30:41

#2.sqrt(15)#

Multiply the radicands together:

#sqrt(20). sqrt(3)# = #sqrt(20 xx 3)# = #sqrt(60)#

Now you can simplify the #sqrt(60# if possible.

This gives us:

#sqrt(60# = #sqrt(2^2 xx 3 xx 5)# = #2.sqrt(3 xx 5)# = #2.sqrt(15)#

Therefore:

#sqrt(20). sqrt(3)# = #2.sqrt(15)#

Hope this helps!