How do you factor 2x^{2}+4x-62x2+4x−6?

2 Answers
anskat
Jun 11, 2018

You cannot (unless you use imaginary numbers, i.e. i).
Maybe check that there is no typo.

Explanation:

The Quadratic Formula: For ax^2" + bx + c = 0ax2+bx+c=0, the values of x (factors) which are the solutions of the equation are given by:
x=(b+-sqrt(4*a*c))/(2*a)x=b±√4⋅a⋅c2⋅a

Here, a=2, b=4 and c=-6, so

x=(4+-sqrt(4*2*(-6)))/(2*2)x=4±√4⋅2⋅(−6)2⋅2

x=(4+-sqrt(-48)/4)x=(4±√−484)

since you cannot take the square root of a negative number (-48), there are no real factors of teh equation. this means that, when plotted on a graph, the X-axis is never crossed.

Jim G.
Jun 11, 2018

2(x+3)(x-1)2(x+3)(x−1)

Explanation:

"take out a "color(blue)"common factor "2take out a common factor 2

=2(x^2+2x-3)=2(x2+2x−3)

"the factors of - 3 which sum to + 2 are + 3 and - 1"the factors of - 3 which sum to + 2 are + 3 and - 1

=2(x+3)(x-1)=2(x+3)(x−1)

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